SOLVED: Which is the equation of a parabola with vertex (0, 0), that opens to the left and has a focal width of 12?
SOLVED: Find the vertex, focus, focal width, and equation of the axis for each parabola. Make a graph. (y-5)^2=12(x-3)
The focal distance of a point on the parabola ${y^2} = 4x$ and above its axis, is 10 units. Its coordinates are A). (9, 6)B). (25, 10)C). (25, -10)D). None of these
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Section 8.1
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SOLUTION: Write the standard equation of the parabola given the two endpoints of the focal width ; (-2,3) and (5,3) with p>0
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